Question

The perimeter of a triangle is $288$ m and the ratio of the sides is $3:4:5$.Find the area of the triangle.

Answer 1

Let,

Sides of triangle are,

$3k,4k$ and 5k

Then the perimeter of triangle is,

$A=3k+4k+5k$

$A=12k$

\end{align}$

But, given that perimeter =$288$ unit

So,

$12k=288$

$k=\frac{288}{12}=24$

Now, sides of triangle are, $3\times 24,4\times 24$ and $24\times 5$ .

=$72$ unit ,$96$ unit and $120$ units.

Hence, this is the answer.