The perimeter of a triangle is $45 c m$ . Length of the second side is twice the length of first side. The third side is $5$ more than the first side. Find the length of each sides.

11, 19, 15

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10, 20, 15

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10, 16, 19

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13, 15, 17

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Solution

The correct option is B $10, 20, 15$
Let the length of first side $= x$
Length of second side $= 2 x$
Length of third side $= x + 5$
Perimeter $= 45 c m$
$x + 2 x + x + 5 = 45 4 x = 45 - 5 4 x = 40 x = 10$
So the sides are
$x = 10$
$2 x = 2 \times 10 = 20 x + 5 = 10 + 5 = 15$
Option $B$ is correct.

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The perimeter of a triangle is 45 cm. Length of the second side is twice the length of first side. The third side is 5 more than the first side. Find the length of each sides.

The correct option is B 10,20,15Let the length of first side =xLength of second side =2xLength of third side =x+5Perimeter =45cmx+2x+x+5=454x=45−54x=40x=10So the sides arex=102x=2×10=20x+5=10+5=15Option B is correct.

The perimeter of a triangle is $45 c m$ . Length of the second side is twice the length of first side. The third side is $5$ more than the first side. Find the length of each sides.

The correct option is B $10, 20, 15$
Let the length of first side $= x$
Length of second side $= 2 x$
Length of third side $= x + 5$
Perimeter $= 45 c m$
$x + 2 x + x + 5 = 45 4 x = 45 - 5 4 x = 40 x = 10$
So the sides are
$x = 10$
$2 x = 2 \times 10 = 20 x + 5 = 10 + 5 = 15$
Option $B$ is correct.