The perimeter of a triangle is $8 + 13 a + 7 a^{2}$ and two of its sides are $2 a^{2} + 3 a + 2$ and $3 a^{2} - 4 a - 1$ . Find the third side of the triangle.

Open in App

Solution

Two sides of triangle are $2 a^{2} + 3 a + 2$ and $3 a^{2} - 4 a - 1$
Let the third side be $s$
Perimeter $= 8 + 13 a + 7 a^{2} =$ $2 a^{2} + 3 a + 2$ $+ 3 a^{2} - 4 a - 1 + s$
$⟹ s = 2 a^{2} + 15 a + 7$
So, the third side of triangle is $= 2 a^{2} + 15 a + 7$

Suggest Corrections

Similar questions

3

8 + 13 a + 7 a^{2} .

2 a^{2} + 3 a + 2

3 a^{2} - 4 a + 1

a^{2} - 2 a + 1

3 a^{2} - 5 a + 3

6 a^{2} - 4 a + 9

14 a^{2} + 20 a + 13

3 a^{2} + 5 a + 1

a^{2} + 10 a - 6

If two sides of a triangle are 8 cm and 6 cm and its perimeter is 26 cm. Find the third side of the triangle.

9 m^{2} - 2 n + 8

4 m^{2} + 3 n

7 m^{2} + 5 n - 12

Join BYJU'S Learning Program