The perimeter of a triangle is.... the sum of its medians.
Greater Than
Let ABC be the triangle and AD, BE and CF be the medians as shown in the figure.
Sum of any two sides of a triangle is greater than twice the median bisecting the third side.
AB + AC > 2 AD, AB +BC > 2 BE and BC + AC > 2 CF
Adding the above you get
2(AB + BC + AC) > 2(AD + BE + CF)
(AB + BC + AC) > AD + BE + CF