Question

The perimeter of a triangle whose coordinates of vertices are (0, 0), (3, 0) and (0, 4) is

• A. 12 units
• B. 3 units
• C. 4 units
• D. 7 units

Answer 1

The correct option is A 12 units

Let the coordinates of A, B and O be (3, 0), (0, 4) and (0, 0) respectively.



Here, OA = 3 units and OB = 4 units.

$AB=\sqrt{(3-0{)}^2+(0-4{)}^2}$

$=\sqrt{3^2+4^4}$

$=\sqrt{25}=5units$

∴ Perimeter of ΔAOB = OA + OB + AB

= 3 + 4 + 5

= 12 units

Hence, the correct answer is option (a).