Question

The perimeter of a triangle with vertices $(0,4),(0,0)$ and $(3,0)$ is

• A. $5$ units
• B. $12$ units
• C. $11$ units
• D. ($7+\sqrt{5}$) units

Answer 1

Answer: (B)

$12$ units

Vertices of triangle $ABC$ are given as $A(0,0),B(0,4)$ and $C(3,0)$

Using the distance formula,

Distance between $P(x_1,y_1)$ and $Q(x_2,y_2)$, is

$PQ=\sqrt{(x_2-x_1{)}^2+(y_2-y_1{)}^2}$

Using this, we get

$AB=4$

$BC=5$ and $AC=3$

Now, the perimeter of the triangle $=AB+BC+AC$

$=4+5+3=12$ units

Hence, option B is correct.