The perimeter of a wheel of a size of a car is 70 cm. How much distance will it cover in 50 revelution.

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Solution

Diameter = 70 cm
radius = 35 cm

so,
distance in one revolution
= circumference of tyre
= 2πr
= 2×(22/7)×35
= 2×22×5
= 220 cm

now,
distance in 50 revolutions = 220×50 = 11000 cm = 11 m

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The perimeter of a wheel of a size of a car is 70 cm. How much distance will it cover in 50 revelution.

Diameter = 70 cm radius = 35 cm so, distance in one revolution = circumference of tyre = 2πr = 2×(22/7)×35 = 2×22×5 = 220 cm now, distance in 50 revolutions = 220×50 = 11000 cm = 11 m

Diameter = 70 cm
radius = 35 cm

so,
distance in one revolution
= circumference of tyre
= 2πr
= 2×(22/7)×35
= 2×22×5
= 220 cm

now,
distance in 50 revolutions = 220×50 = 11000 cm = 11 m