The perimeter of an equilateral triangle is 60m. The area is
10√3 m2
15√3 m2
20√3 m2
100√3 m2
Let side of equilateral triangle be ‘a’ m.
∴a+a+a=60⇒a=20 m
Area =√34(20)(20) m2=100√3 m2
Find the area of the regular hexagon whose side length is 6 m.