The perimeter of an isosceles triangle is $32 c m$ and each of the equal sides is $5 / 6$ times of the base. What is the area (in ${c m}^{2}$ ) of the triangle?

39

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48

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Solution

The correct option is B $48$
Let $b$ be the base and $a$ be other two sides
$b + 2 \times a = 32$
$\Rightarrow b = 12, a = 10 (∵ a = \frac{5}{6} b)$
Area of triangle $= \sqrt{16 (16 - 2) (16 - 10) (16 - 10)} = 48 {c m}^{2}$

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The perimeter of an isosceles triangle is 32cm and each of the equal sides is 5/6 times of the base. What is the area (in cm2) of the triangle?

The correct option is B 48Let b be the base and a be other two sidesb+2×a=32⇒b=12,a=10(∵a=56b)Area of triangle =√16(16−2)(16−10)(16−10)=48cm2

The perimeter of an isosceles triangle is $32 c m$ and each of the equal sides is $5 / 6$ times of the base. What is the area (in ${c m}^{2}$ ) of the triangle?

The correct option is B $48$
Let $b$ be the base and $a$ be other two sides
$b + 2 \times a = 32$
$\Rightarrow b = 12, a = 10 (∵ a = \frac{5}{6} b)$
Area of triangle $= \sqrt{16 (16 - 2) (16 - 10) (16 - 10)} = 48 {c m}^{2}$