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Question

the perimeter of an isosceles triangle is 42 cm and its base is3/2 times each of the equal sides find the length of each side and area of triangle

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Solution

Let ABC be an isosceles .Let AB = AC = xthen BC = 3x2Now, perimeter = 42 cmAB+AC+BC = 42x+x+3x2 = 427x2 = 42x = 12So, AB = AC = 12 cmNow, BC = 18 cmNow, a = 12 cm; b = 12 cm; c = 18 cmSemi perimeter, s = 422 = 21 cmNow, area = ss-as-bs-c=2121-1221-1221-18=21×9×9×3=277 cm2

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