Question

The perimeter of an isosceles triangle is 90m. if the length of the two equal sides is $\frac{3}{4}$ of the length of unequal side, find the dimensions of the triangle?

Answer 1

Let the length of unequal side be $x$.

Thus, length of equal side will be $\frac{3}{4}x$

According to the given condition,

$\frac{3}{4}x+\frac{3}{4}x+x=90$

$10x=360$

$\Rightarrow x=36$

$\frac{3}{4}x=27$

Thus sides of the triangle are $27m,27m,36m$