The perimeter of circle is - cm- then the area

The correct option is D π/4 Given, Circumferenceof a circle of radius r = 2π r #160; = π #160; r = 12 Area of a circle of radius r =πr^ ...

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Area of Circle

The perimeter...

Question

The perimeter of circle is $π$ cm, then the area

\frac{π^{2}}{4}

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\frac{π^{2}}{2}

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\frac{π}{2}

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\frac{π}{4}

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y = \sqrt{4 - x^{2}}, y \geq \sqrt{2} sin (\frac{x π}{2 \sqrt{2}})

y = \sqrt{4 - x^{2}}, y \geq \sqrt{2} s i n (\frac{x π}{2 \sqrt{2}})

f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} - 2 sin x, & - π \leq x \leq \frac{- π}{2} a cos (x) + b, & \frac{- π}{2} < x < 0 - 2 + cos x, & 0 \leq x \leq \frac{π}{2} c sin x, & \frac{π}{2} < x \leq π \end{matrix} ⎫ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎬ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎭

[- π, π],

f (x)

If, $f (x) = c o s [π^{2}] x + c o s [- π^{2}] x,$ where [x] stands for greatest integer function, then

f (x) = cos [π^{2}] x + cos [- π^{2}] x

f (\frac{- π}{4})

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