The perimeter of ΔABC is 50 cm. Its sides AB,BC and AC are respectively 15 cm, 10 cm and (x+4) cm. Find the value of x?
Given: Perimeter =50 cm
Sides of the given triangle are 15 cm, 10 cm, and (x+4) cm.
We know that perimeter of the triangle is sum of all sides.
∴15+10+x+4=50
⇒x+29=50
⇒x=50−29