The perimeter of the given triangle is 12 cm. Find the measure of the side AB.

4

Open in App

Solution

The correct option is A 4
Given:

AC = $5 c m$ and BC = $3 c m$

Perimeter of $Δ A B C$ = $12 c m$

Let the length of the side AB = $x$ units
Now,
Perimeter of a triangle = Sum of lengths of all the sides
$∴ 12 = 3 + 5 + x$
$\Rightarrow x = [12 - (3 + 5)]$
$= (12 - 8) = 4 cm$
Hence, the measure of side $A B = 4 c m$

Suggest Corrections

Similar questions

The perimeter of an isosceles triangle is 12 cm and its unequal side is 5 cm. Find other sides of the triangle.

Find the perimeter of a triangle whose sides are $12 c m, 6 c m$ and $15 c m$ .

B C = 14 c m

A B = 1 \frac{1}{2} l (B C)

Join BYJU'S Learning Program