Question

The perimeter of the parallelogram is $140cm$. If one of the sides is greater than the other by $10cm,$ find the lengths of the sides of the parallelogram.

Answer 1

The perimeter of the parallelogram of sides $a$ and $b$ is given by $2\left(a+b\right)$

Let one side be $b$

So, on the other side, $a=\left(b+10\right)$

So, perimeter =

$$\begin{gathered} 2\left(\left(b+10\right)+b\right)=140 \\ 2b+10=70 \\ 2b=60 \\ b=30 \end{gathered}$$

$$\begin{gathered} a=(30+10)=40cm \\ b=30cm \end{gathered}$$

Hence, the lengths of the parallelogram are $40,30.$