Question

The perimeter of the quadrant of a circle is 25 cm. Find its area.

Answer 1

Let radius = r

Perimeter = radius + radius + length of arc

Perimeter of quadrant $=r+r+\frac{angle}{360}\times 2\times \pi \times r=25$

$2r+[\frac{1}{4}\times 2\times \frac{22}{7}\times r]=25$

$\frac{25}{7}\times r=25$

r = 7

$Area=\frac{angle}{360}\times \pi \times r\times r$

$\frac{1}{4}\times \frac{22}{7}\times 7\times 7=38.5c{m}^2$