The perimeter of the quadrilateral $A P O Q$ is $26 c m$ and $A P = 10 c m$ . $O$ is the centre of the circle. Then the radius of the circle is (where $A P$ and $A Q$ are the tangents from $A$ )

6 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 c m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

8 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $3 c m$
Perimeter is sum of all sides of a quadrilateral.

Perimeter of quadrilateral will be $(A P + A Q + O P + O Q) = 26$ cm.
Now $A P = A Q$ ( tangents from same point is equal in length )
and $O P = O Q$ = radius.

Therefore , $26 = 20 + 2 r$ ;
So, $r = 3$ cm.

Suggest Corrections

Similar questions

A is a point at a distance 13 cm from the centre O of a circle of radius 5 cm. AP and AQ are the tangents to the circle at P and Q. If a tangent BC is drawn at a point R lying on the minor PQ to intersect AP at B and AQ at C, find the perimeter of the $Δ A B C$ .

Q. Question 14
A is a point at a distance 13 cm from the centre O of a circle of radius 5 cm. AP and AQ are the tangents to the circle at P and Q . If a tangent BC is drawn at a point R lying on the minor arc PQ to intersect AP at B and AQ at C, find the perimeter of the ∆ABC.

In the adjoining figure, O is the centre of a circle. Chords AB and CD intersect at P. If AB = 16 cm, CP = 6 cm, PD = 8 cm and AP $>$ PB. Then, AP is–

Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct a pair of tangents to the circle and find their lengths.

Q. AP and PQ are tangents drawn from a point A to a circle with centre O and radius 9 cm. If OA = 15 cm, then AP + AQ =

(a) 12 cm

(b) 18 cm

(c) 24 cm

(d) 36 cm

Join BYJU'S Learning Program

The perimeter of the quadrilateral APOQ is 26 cm and AP=10 cm. O is the centre of the circle. Then the radius of the circle is (where AP and AQ are the tangents from A)

The correct option is B 3 cmPerimeter is sum of all sides of a quadrilateral.Perimeter of quadrilateral will be (AP+AQ+OP+OQ)=26 cm.Now AP=AQ ( tangents from same point is equal in length ) and OP=OQ= radius.Therefore , 26=20+2r ;So, r=3 cm.

The perimeter of the quadrilateral $A P O Q$ is $26 c m$ and $A P = 10 c m$ . $O$ is the centre of the circle. Then the radius of the circle is (where $A P$ and $A Q$ are the tangents from $A$ )

The correct option is B $3 c m$
Perimeter is sum of all sides of a quadrilateral.

Perimeter of quadrilateral will be $(A P + A Q + O P + O Q) = 26$ cm.
Now $A P = A Q$ ( tangents from same point is equal in length )
and $O P = O Q$ = radius.

Therefore , $26 = 20 + 2 r$ ;
So, $r = 3$ cm.