The perimeter of the shaded portion is 104.56 cm
If true then enter $1$ and if false then enter $0$

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Solution

$T h e g i v e n r e c t a n g l e h a s b e e n c r o p p e d b y 4 q u a r t e r c i r c l e s o f r a d i u s 2 c m a t t h e 4 c o r n e r s . ∴ t h e l e n g t h o f t h e c u r v e d l i n e s = c = c i r c u m f e r e n c e o f a c i r c l e o f r a d i u s 2 c m = 2 π \times 2 = 4 π . . . . . (i) T h e l e n g t h o f t h e s h a d e d p a r t a l o n g l o n g e r s i d e = l = (28 - 2 \times 2) c m = 24 c m . . . . . (i i) T h e l e n g t h o f t h e s h a d e d p a r t a l o n g s h o e t e r s i d e = b = (26 - 2 \times 2) c m = 22 c m . . . . . (i i i) N o w t h e p e r i m e t e r o f t h e s h a d e d p a r t = 2 (l + b) + c = 2 (24 + 22) c m + 4 π c m (f r o m i, i i & i i i) = (92 + 4 \times 3.14) c m = 104.56 c m . A n s - T h e p e r i m e t e r o f t h e s h a d e d p a r t = 104.56 c m .$

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