Question

The perimeter of the trepezium is 52 cm and its each non-parallel side is equal to 10 cm with its height 8 cm . Its area is

• A. $124c{m}^2$
• B. $118c{m}^2$
• C. $128c{m}^2$
• D. $112c{m}^2$

Answer 1

Answer: (C)

$128c{m}^2$

Using pythagoras theorem, we have

$x=\sqrt{{10}^2-8^2}$

= 6 cm

$\therefore y+10+10+x+y+x=52$

$2y+20+12=52\Rightarrow 2y=20$

y = 10 cm

Area = $\frac{1}{2}\times (y+x+y+x)\times 8=16\times 8$

$=128c{m}^2$