The perimeter of △ABC is 18cm. If AB = 5 cm and QR = 7cm, then the length of PQ (in cm) is
In ΔABC and ΔPQR,
AB = PR = 5 cm
BC = PQ
AC = QR = 7 cm
∴ ΔABC≅ΔPQR by SSS criterion.
Given, perimeter of △ABC = 18cm
⇒ AB + AC + BC = 18
Substituting the values of AB and AC, we get,
5+7+BC = 18
⇒ BC = 18 - 5 - 7 = 6 cm
Since BC = PQ, we get PQ = 6 cm