Question

The perimeter of triangle with vertices at $(1,0,0),(0,1,0)and(0,0,1)$ is :

• A. $3$
• B. $2$
• C. $2\sqrt{2}$
• D. $3\sqrt{2}$

Answer 1

The correct option is D $3\sqrt{2}$

REF.Image

$AB=\sqrt{1+1+0}=\sqrt{2}$

$BC=\sqrt{0+1+1}=\sqrt{2}$

$AC=\sqrt{1+0+1}=\sqrt{2}$

Hence, perimeter of $△ABC$ is given by

$AB+BC+AC=3\sqrt{2}$