The perimeter of two similar triangle are $30 c m$ and $20 c m$ . If one side of first triangle is $12 c m$ determine the corresponding side of second triangle.

8 c m

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4 c m

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3 c m

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16 c m

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Solution

The correct option is C $8 c m$
Let the two similar triangles be $△ A B C$ and $△ D E F$
$∴ \frac{A B}{D E} = \frac{B C}{E F} = \frac{A C}{D F} = \frac{P_{1}}{P_{2}}$
$\Rightarrow \frac{A B}{D E} = \frac{P_{1}}{P_{2}}$
$\Rightarrow \frac{12}{D E} = \frac{30}{20}$
$\Rightarrow D E = 8 c m$

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The perimeter of two similar triangle are 30 cm and 20 cm. If one side of first triangle is 12 cm determine the corresponding side of second triangle.

The correct option is C 8 cmLet the two similar triangles be △ABC and △DEF∴ABDE=BCEF=ACDF=P1P2⇒ABDE=P1P2⇒12DE=3020⇒DE=8 cm

The perimeter of two similar triangle are $30 c m$ and $20 c m$ . If one side of first triangle is $12 c m$ determine the corresponding side of second triangle.

The correct option is C $8 c m$
Let the two similar triangles be $△ A B C$ and $△ D E F$
$∴ \frac{A B}{D E} = \frac{B C}{E F} = \frac{A C}{D F} = \frac{P_{1}}{P_{2}}$
$\Rightarrow \frac{A B}{D E} = \frac{P_{1}}{P_{2}}$
$\Rightarrow \frac{12}{D E} = \frac{30}{20}$
$\Rightarrow D E = 8 c m$