Question

The perimeter of two similar triangles $ABC$ and $LMN$ are $60cm$ and $48cm$ respectively. If $LM=8cm$, then what is the length of $AB$?

Answer 1

Using BPT we get

$\frac{Perimeter\left(△ABC\right)}{Perimeter\left(△LMN\right)}=\frac{AB}{LM}=\frac{BC}{MN}=\frac{AC}{LN}$

So, $\frac{60}{48}=\frac{AB}{8}$

So, $AB=10㎝$