The perimeter of two similar triangles $A B C$ and $P Q R$ are $36 c m$ and $24 c m$ respectively. If $P Q = 10 c m$ then the length of $A B$ is

18 c m

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12 c m

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15 c m

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30 c m

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Solution

The correct option is C $15 c m$
$△ A B C = △ P Q R$ , then
$\frac{Perimeter of △ A B C}{Perimeter of △ P Q R} = \frac{A B}{P Q} = \frac{B C}{Q R} = \frac{A C}{P R}$
$\frac{36}{24} = \frac{A B}{10}; A B = \frac{36}{24} \times 10 = 15 c m$ .

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The perimeter of two similar triangles ABC and PQR are 36 cm and 24 cm respectively. If PQ=10 cm then the length of AB is

The correct option is C 15 cm△ABC=△PQR, thenPerimeter of△ABCPerimeter of△PQR=ABPQ=BCQR=ACPR3624=AB10;AB=3624×10=15 cm.

The perimeter of two similar triangles $A B C$ and $P Q R$ are $36 c m$ and $24 c m$ respectively. If $P Q = 10 c m$ then the length of $A B$ is

The correct option is C $15 c m$
$△ A B C = △ P Q R$ , then
$\frac{Perimeter of △ A B C}{Perimeter of △ P Q R} = \frac{A B}{P Q} = \frac{B C}{Q R} = \frac{A C}{P R}$
$\frac{36}{24} = \frac{A B}{10}; A B = \frac{36}{24} \times 10 = 15 c m$ .