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Question

The perimeters of two similar triangles ABC and PQR are 32 cm and 24 cm respectively. If PQ = 12 cm, find AB.

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Solution

ΔABCΔPQR

ABPQ=BCQR=ACPR=AB+BC+ACPQ+QR+PR (Corresponding sides are proportional)

AB+BC+ACPQ+QR+PR=ABPQ


Perimeter of ABCPerimeter of PQR=ABPQ

3224=AB12

AB=3224×12=16


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