The perimeters of two similar triangles ABC and PQR are 32 cm and 24 cm respectively. If PQ = 12 cm, find AB.
ΔABC∼ΔPQR
ABPQ=BCQR=ACPR=AB+BC+ACPQ+QR+PR (Corresponding sides are proportional)
⇒AB+BC+ACPQ+QR+PR=ABPQ
⇒Perimeter of ABCPerimeter of PQR=ABPQ
⇒3224=AB12
⇒AB=3224×12=16