The perimeters of two similar triangles are $25 c m$ and $15 c m$ respectively. If one side of first triangle is $9 c m$ , then the corresponding side of the other triangle is

6.2 c m

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3.4 c m

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5.4 c m

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8.4 c m

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Solution

The correct option is D $5.4 c m$
$T h e p e r i m e t e r o f t r i a n g l e i s 25 c m a n d 15 c m . T h e r a t i o o f P e r i m e t e r o f t r i a n g l e i s 25 : 15 = 5 : 3 T h e f i r s t s i d e i s 9 c m, l e t t h e o t h e r s i d e = x H e n c e, \frac{9}{x} = \frac{5}{3} \Rightarrow x = \frac{3 \times 9}{5} = \frac{27}{5} = 5.4 c m$

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The perimeters of two similar triangles are 25cm and 15cm respectively. If one side of first triangle is 9cm, then the corresponding side of the other triangle is

The correct option is D 5.4cmTheperimeteroftriangleis25cmand15cm.TheratioofPerimeteroftriangleis25:15=5:3Thefirstsideis9cm,lettheotherside=xHence,9x=53⇒x=3×95=275=5.4cm

The perimeters of two similar triangles are $25 c m$ and $15 c m$ respectively. If one side of first triangle is $9 c m$ , then the corresponding side of the other triangle is