The period of a pendulum for small swings near the Earth depends on its.

Length and amplitude of swing only

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Amplitude of swing and mass only

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Length only

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Amplitude only

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Length, mass, and amplitude of swing.

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Solution

The correct option is B Length only
Time period of the pendulum $T = 2 π \sqrt{\frac{l}{g}}$ ,
where $T =$ Time period
$l$ = length of the pendulum
$g$ = gravitational acceleration.
So, the period depends on length only.

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