Question

The period of oscillation of a particle in SHM is $4$ sec and its amplitude of vibration is $4$ cm. The distance of the particle $1/3sec$ after passing the mean position is

• A. 1.33 cm
• B. 1.66 cm
• C. 2 cm
• D. 2.33 cm

Answer 1

Answer: (C)

2 cm

$T=4$ sec ; $\omega =\frac{2\pi }{4}=\frac{\pi }{2}\frac{rad}{sec}$
$A=4cm$

$x=A$ sin $wt$
$=4cm\times sin\frac{\pi }{2}\times \frac{1}{3}=2cm$
Answer is option C