The period of oscillation of a simple pendulum in the experiment is recorded as $2.63 s, 2.56 s, 2.42 s, 2.71 s$ and $2.80 s$ . Find the average absolute error.

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Solution

Average value
= $\frac{2.63 + 2.56 + 2.42 + 2.71 + 2.80}{5} = 2.62 s$
Now $| △ T_{1} | = 2.63 - 2.62 = 0.01$
$| △ T_{2} | = 2.62 - 2.56 = 0.06$
$| △ T_{3} | = 2.62 - 2.42 = 0.20$
$| △ T_{4} | = 2.71 - 2.62 = 0.09$
$| △ T_{5} | = 2.80 - 2.62 = 0.18$
Mean absolute error
$△ T = \frac{| △ T_{1} | + | △ T_{2} | + | △ T_{3} | + | △ T_{4} | + | △ T_{5} |}{5} = \frac{0.54}{5} = 0.108 = 0.11 s$

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