The period of oscillation of a simple pendulum in the experiment is recorded as 2.63 s, 2.56 s, 2.42, 2.71 s and 2.80 s respectively. Find the average absolute error.

0.12s

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0.11 s

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0.108 s

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none of these

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Solution

The correct option is D
none of these

$\begin{matrix} O b s e r v a t i o n x & D i f f e r e n c e & (D i f f e r n c e)^{2} 2.63 & 0.01 & 0.0001 2.56 & 0.06 & 0.0036 2.42 & 0.20 & 0.0400 2.71 & 0.09 & 0.0081 2.80 & 0.18 & 0.0324 Avg = 2.624 Rounding off to 3 digits Avg = 2.62 \end{matrix}$

$\begin{matrix} v a r i a n c e i s a v e r a g e o f | △ x |^{2} = \frac{\sum (△ x)^{2}}{5} \end{matrix}$

$S t a n d a r d d e v i a t i o n = \sqrt{0.0168}$

= 0.129

Round off = 0.13

Average absolute error = $\pm$ 0.13 sec

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