Question

The period of oscillation of a simple pendulum in the experiment is recorded as 2.63 s, 2.56 s, 2.42, 2.71 s and 2.80 s respectively. Find the average absolute error.

• A. 0.12s
• B. 0.11 s
• C. 0.108 s
• D. none of these

Answer 1

The correct option is D

none of these

$\begin{array}{ccc}Observationx& Difference& (Differnce{)}^2\\ 2.63& 0.01& 0.0001\\ 2.56& 0.06& 0.0036\\ 2.42& 0.20& 0.0400\\ 2.71& 0.09& 0.0081\\ 2.80& 0.18& 0.0324\\ \text{Avg = 2.624}& & \\ \text{Rounding off to 3 digits}& & \\ \text{Avg = 2.62}& & \end{array}$

$\begin{array}{c}varianceisaverageof\\ |△x{|}^2=\frac{\sum (△x{)}^2}{5}\end{array}$

$Standarddeviation=\sqrt{0.0168}$

= 0.129

Round off = 0.13

Average absolute error = $\pm$ 0.13 sec