Question

The period of oscillation of a simple pendulum is inversely proportional to the square root of acceleration due to gravity.

• A. True
• B. False

Answer 1

The correct option is A True

1. The time taken by a pendulum to complete one oscillation is called the time period.
2. The time period of a simple pendulum is given as, $T=2\mathrm{\pi }\sqrt{\frac{\mathit{l}}{\mathit{g}}}$, where $l$ is length of the pendulum and $g$ is acceleration due to gravity.
3. As $\mathrm{\pi }$ and $l$ are constant, it can be said that, $T\propto \sqrt{\frac{1}{g}}$.
4. Therefore, the time period of a simple pendulum is inversely proportional to the square root of acceleration due to gravity.

Hence, the given statement is true.