Question

The period of oscillation of a simple pendulum of length L suspended from the roof of a vehicle which moves without friction down an inclined plane of inclination $\alpha$ is given by

• A. $2\pi \sqrt{\frac{L}{gcos\alpha }}$
• B. $2\pi \sqrt{\frac{L}{gsin\alpha }}$
• C. $2\pi \sqrt{\frac{L}{g}}$
• D. $2\pi \sqrt{\frac{L}{gtan\alpha }}$

Answer 1

The correct option is A $2\pi \sqrt{\frac{L}{gcos\alpha }}$

Here, $g_{eff}=gcos\alpha$
So,T=$2\pi \sqrt{\frac{L}{gcos\alpha }}$