The period of sin 2- is

We know that sin^2 θ =1 cos 2 θ2=12 cos 2 θ2 We know that period of cosθ is π. Thus, the period of cos mθ is π|m|. Thus, Period of nbsp; cos 2 θ =2π2=π ...

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Standard XII

Mathematics

Sum of Cosines of Angles in Arithmetic Progression

The period of...

Question

The period of $s i n^{2} θ$ is

π^{2}

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π

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2 π

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\frac{π}{2}

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Solution

The correct option is B $π$
$s i n^{2} θ = \frac{1 - c o s 2 θ}{2}$
Period = $\frac{2 π}{2} = π$

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The period of sin2θ is

The correct option is B πsin2θ=1−cos2θ2 Period =2π2=π

The period of $s i n^{2} θ$ is

The correct option is B $π$
$s i n^{2} θ = \frac{1 - c o s 2 θ}{2}$
Period = $\frac{2 π}{2} = π$