The period of sinπ4[x]+cosπx2+cotπ3[x], where [x] denotes the integral part of x is -
A
8
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B
4
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C
3
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D
24
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Solution
The correct option is D24 We have sinπ4[x] is periodic of period 8, cosπx2 is periodic of period 4 and cotπ3[x] is periodic of period 3. They can be easily verified.
As sinπ4[x+8]=sin(2π+π4[x])=sinπ4[x] and cosπ2(4+x)=cos(2π+π2x)=cosπx2 similar proof for cotπ3[x].
Now the period of the function f(x)=sinπ4[x]+cosπx2+cotπ3[x] will be LCM of 8,4,3 and it is 24.