The period of the function: f(x)=eln(sinx)+tan3x−cosec(3x−5) is bπ. Find b
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Solution
f(x)=eln(sinx)+tan3x−cosec(3x−5)=sinx+tan3x−cosec(3x−5) Period of sinx,tan3x and cosec(3x−5) are 2π,π and 2π3 ⇒ Period of f(x) is = L.C.M of 2π,π and 2π3=2π Hence b=2