The period of the function $f (x) = (sin 3 x) + | cos 6 x |$ is

π

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2 π / 3

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2 π

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π / 2

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Solution

The correct option is B $2 π / 3$
Given function is $f (x) = sin 3 x + | cos 6 x |$
Period of $sin x$ is $2 π$

$\Rightarrow$ period of $sin 3 x$ is $\frac{2 π}{3}$
Period of $| cos x |$ is $π$

$\Rightarrow$ period of $| cos 6 x |$ is $\frac{π}{6}$

Period of $f (x)$ is L.C.M of denomirator of both functions dividied by H.C.F
of numerator of both

$\Rightarrow$ period of $f (x)$ is $\frac{2 π}{3}$

So, option B is correct

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The period of the function f(x)=(sin3x)+|cos6x| is

The period of the function $f (x) = (sin 3 x) + | cos 6 x |$ is