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Question

The period of the function f(x)=3tan(x3+π2)=

A
2π
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B
3π
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C
π3
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Solution

The correct option is B 3π
Given: f(x)=3tan(x3+π2)

Now, consider a function g(x)=tanx
f(x)=ag(bx+c), where a=3,b=13,c=π2
Now, period of g(x) is T=π
Thus, Period of f(x) will be T|b|=π1/3=3π

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