The period of the function f(x) = sin 3x is

2 π

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\frac{2 π}{3}

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6 π

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8 π

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Solution

The correct option is B $\frac{2 π}{3}$
Period of sin ax = $\frac{2 π}{a}$
So, Period of sin 3x will be = $\frac{2 π}{3}$

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Similar questions

f (x) = sin 3 x cos [3 x] - cos 3 x sin [3 x],

R \to R

sin x cos y [f (2 x + 2 y) - f (2 x - 2 y)] = cos x sin y [f (2 x + 2 y) + f (2 x - 2 y)]

f^{'} (0) = \frac{1}{2}

f_{1} (x) = {sin}^{- 1} (cos ({sin}^{2} x)),

f_{2} (x) = {cos}^{- 1} (sin ({cos}^{2} x)),

f_{3} (x) = {sin}^{- 1} (cos ({cos}^{2} x))

f_{4} (x) = {cos}^{- 1} (sin ({sin}^{2} x)) .

\to

f (2 x + 3) + f (2 x + 7) = 2, \forall x ϵ R

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