The period of the function f(x)=sin(2πx+π8)+2sin(3πx+π3) is
A
1
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B
23
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C
2
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D
3
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Solution
The correct option is C2 f(x)=sin(2πx+π8)+2sin(3πx+π3)
Period of sin(2πx+π8) is T1=2π2π=1
Period of 2sin(3πx+π3) is T2=2π3π=23 ∴L.C.M.(T1,T2)=L.C.M.of(1,2)H.C.F.of(1,3)=21=2
Hence, period of f(x) is 2.