The period of the SHM of a particle with the maximum velocity $50 c m / s$ and maximum acceleration $10 c m / s^{2}$ is

31.42 s

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6.284 s

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3.142 s

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0.3124 s

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Solution

The correct option is A $31.42 s$
$\begin{matrix} V_{max} = A w = 50 m / s a_{m a s} = A w^{2} = 10 c m / s^{2} \frac{1}{w} = 5 w = \frac{1}{5} = \frac{2 π}{T} T = 10 π = 31.42 sec ∴ O p t i o n (A) i s c o r r e c t . \end{matrix}$

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