Question

The periodic table consists of $18$ groups. An isotope of copper, on bombardment with protons, undergoes a nuclear reaction yielding element $X$ as shown below. To which group, the element $X$ belongs in the periodic table?
${}_{29}^{63}Cu{+}_1^{1}H⟶6_0^{1}n+\alpha +2_1^{1}H+X$

Answer 1

$8$
The given nuclear reaction is
${}_{29}^{63}Cu{+}_1^{1}H⟶$ $6_0^{1}n{+}_2^{4}He+2_1^{1}H{+}_{26}^{52}Fe$
The element ${}_{26}^{52}Fe$ belongs to $8$th group of periodic table.