Question

The periodic table consists of 18 groups. An isotope of copper, on bombardment with protons, undergoes a nuclear reaction yielding element $X$ as shown below. The group to which, element $X$ belongs in the periodic table is _________ .
${}_{29}^{63}\text{Cu}{+}_1^1\text{H}⟶6{}_0^{1}n+\alpha +2_1^1\text{H}+X$

Answer 1

${}_{29}^{63}\text{Cu}{+}_1^1\text{H}⟶6{}_0^{1}n+\alpha +2_1^1\text{H}+X$

$\alpha ={}_2^{4}He$

For element X, $Z=29+1-6\left(0\right)-2-2\left(1\right)=26$
$A=63+1-6\left(1\right)-4-2\left(1\right)=52$
Hence, the element X is iron ${}_{26}^{52}Fe$.
It belongs to group 8.
${}_{29}^{63}\text{Cu}{+}_1^1\text{H}⟶6{}_0^{1}n+\alpha +2_1^1\text{H}{+}_{26}^{52}Fe$.