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Question

The perpendicular bisector of the line segment joining P(1,4) and Q(k,3) has y-intercept 4. Then a possible value of k is

A
1
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B
2
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C
-2
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D
-4
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Solution

The correct option is D -4
Slope of PQ=34k1=1k1
Slope of perpendicular bisector of PQ=(k1)
Also mid point of PQ(k+12,72) .
Equation of perpendicular bisector is
y72=(k1)(xk+12)2y7=(k1)x(k21)2(k1)x2y+(8k2)=0y -intercept =8k22=48k2=8 or k2=16k=±4

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