The perpendicular distance from the origin is $5$ units and the angle made by the perpendicular with the positive $x -$ axis is $30^{o}$ .Find the equation of the line?

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Solution

$x c o s α + y s i n α = p x c o s 30^{\circ} + y s i n 30^{\circ} = 5 (\frac{\sqrt{3} x}{2}) + (\frac{y}{2}) = 5 \sqrt{3} x + y = 10$

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The perpendicular distance from the origin is 5 units and the angle made by the perpendicular with the positive x−axis is 30o.Find the equation of the line?

xcosα+ysinα=pxcos30∘+ysin30∘=5(√3x2)+(y2)=5√3x+y=10

The perpendicular distance from the origin is $5$ units and the angle made by the perpendicular with the positive $x -$ axis is $30^{o}$ .Find the equation of the line?

$x c o s α + y s i n α = p x c o s 30^{\circ} + y s i n 30^{\circ} = 5 (\frac{\sqrt{3} x}{2}) + (\frac{y}{2}) = 5 \sqrt{3} x + y = 10$