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Question


The perpendicular distance from the origin to the radical axis of the circles 2x2+2y23xy+3=0 and 3x2+3y2x+y1=0 is

A
2
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B
1174
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C
52
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D
52
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Solution

The correct option is C 1174
s1:2x2+2y23xy+3=0
s2:3x2+3y2x+y1=0
So, equation of radial axis is
s1s2=0
(9x3y+9)(2x+2y2)=0
7x5y+11=0
7x+5y11=0
Perpendicular distance from P(0,0) to 7x+5y11=0 is
d=|1174|=1174

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