The perpendicular distance of a line from origin is 2 units and the perpendicular makes an angle α with X-axis such that sinα=13. The equation of line is .
A
2√2x+y=6
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B
2√2x−y=6
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C
x+2√2y=6
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D
x−2√2y=6
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Solution
The correct option is A2√2x+y=6 Perpendiculardistance,p=2Given,sinα=13⇒cosα=±√1−sin2α=±√1−19=±2√23Hence,theequationofthelinebynormalformis±2√2x3+y3=2⇒2√2x+y=6or−2√2x+y=6