The perpendicular distance of the point $(x, y, z)$ from the x-axis is

\sqrt{x^{2} + y^{2}}

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\sqrt{y^{2} + z^{2}}

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\sqrt{z^{2} + x^{2}}

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\sqrt{x^{2} + y^{2} + z^{2}}

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Solution

The correct option is B $\sqrt{y^{2} + z^{2}}$
The given point is $(x, y, z)$
$∴$ by distance formula
Distance = $\sqrt{(x - x)^{2} + (y - 0)^{2} + (z - 0)^{2}} = \sqrt{y^{2} + z^{2}}$

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