The perpendicular from A on the side BC of ABC intersects BC at D such that DB=3CD. Prove that 2ABsquare = 2ACsquare+BCsquare.

Open in App

Solution

Suggest Corrections

Similar questions

A

B C

B C

D

D B = 3 C D

2 A B^{2} = 2 A C^{2} + B C^{2}

Δ A B C

2 A B^{2} = 2 A C^{2} + B C^{2}

The perpendicular from A on side BC of a ΔABC intersect BC at D such that DB = 3 CD. Prove that 2 AB² = 2 AC² + BC²

Δ A B C

2 A B^{2} = 2 A C^{2} + B C^{2}

The perpendicupar from A on side BC of a triangle ABC intersects bc at d such that db=3cd prove that 2qb square= 2ac square + bc square.

Join BYJU'S Learning Program