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Standard VIII

Physics

Law of Floatation

The person of...

Question

The person of mass $60 k g$ is balanced in mid air by holding one end of a light rope passing over a smooth pulley with the counter weight of $60 k g$ connected to the other end as shown. He starts climbing up the rope with an acceleration of $2 m / s^{2}$ with relative to it. Time taken for the person to reach the pulley will be

6 s e c

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2 \sqrt{5} s e c

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Infinity

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None of these

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Solution

The correct option is A $6 s e c$
When the person is climbing up the rope $.$ the counter weight also moves up $.$
Therefore $,$ distance to be moved by the person will be $18 + 18 = 36 c m$
$\begin{matrix} \frac{1}{2} a_{r e l} t^{2} = 36 ∴ \frac{1}{2} \times 2 \times t^{2} = 36 \Rightarrow t = 6 sec \end{matrix}$
Hence,
option $(A)$ is correct answer.

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The correct option is A 6secWhen the person is climbing up the rope. the counter weight also moves up.Therefore, distance to be moved by the person will be 18+18=36cm12arelt2=36∴12×2×t2=36⇒t=6secHence,option (A) is correct answer.